$window.hasInput
Checks if a window has an input field
Usage
$window.hasInput
$window.hasInput(<window_id>)
Description
Returns 1 if the window specified by <window_id> has an input field and 0 otherwise. The form with no parameters works on the current window. If the specified window doesn't exist then 0 is returned.
See also
$window.hasoutput

Index, Functions